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(9y^2-17y-12)+(5y^2+12y+4)=0
We get rid of parentheses
9y^2+5y^2-17y+12y-12+4=0
We add all the numbers together, and all the variables
14y^2-5y-8=0
a = 14; b = -5; c = -8;
Δ = b2-4ac
Δ = -52-4·14·(-8)
Δ = 473
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{473}}{2*14}=\frac{5-\sqrt{473}}{28} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{473}}{2*14}=\frac{5+\sqrt{473}}{28} $
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